Class Solution
-
- All Implemented Interfaces:
public final class Solution
693 - Binary Number with Alternating Bits\.
Easy
Given a positive integer, check whether it has alternating bits: namely, if two adjacent bits will always have different values.
Example 1:
Input: n = 5
Output: true
Explanation: The binary representation of 5 is: 101
Example 2:
Input: n = 7
Output: false
Explanation: The binary representation of 7 is: 111.
Example 3:
Input: n = 11
Output: false
Explanation: The binary representation of 11 is: 1011.
Constraints:
<code>1 <= n <= 2<sup>31</sup> - 1</code>
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
Modifier and Type Method Description final Boolean
hasAlternatingBits(Integer n)
-
-
Method Detail
-
hasAlternatingBits
final Boolean hasAlternatingBits(Integer n)
-
-
-
-