Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    1043 - Partition Array for Maximum Sum\.

    Medium

    Given an integer array arr, partition the array into (contiguous) subarrays of length at most k. After partitioning, each subarray has their values changed to become the maximum value of that subarray.

    Return the largest sum of the given array after partitioning. Test cases are generated so that the answer fits in a 32-bit integer.

    Example 1:

    Input: arr = 1,15,7,9,2,5,10, k = 3

    Output: 84

    Explanation: arr becomes 15,15,15,9,10,10,10

    Example 2:

    Input: arr = 1,4,1,5,7,3,6,1,9,9,3, k = 4

    Output: 83

    Example 3:

    Input: arr = 1, k = 1

    Output: 1

    Constraints:

    • 1 <= arr.length <= 500

    • <code>0 <= arri<= 10<sup>9</sup></code>

    • 1 &lt;= k &lt;= arr.length

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer maxSumAfterPartitioning(IntArray arr, Integer k)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait