Class Solution
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public final class Solution
87 - Scramble String\.
Hard
We can scramble a string s to get a string t using the following algorithm:
If the length of the string is 1, stop.
If the length of the string is > 1, do the following:
Given two strings
s1
ands2
of the same length , returntrue
ifs2
is a scrambled string ofs1
, otherwise, returnfalse
.Example 1:
Input: s1 = "great", s2 = "rgeat"
Output: true
Explanation: One possible scenario applied on s1 is: "great" --> "gr/eat" // divide at random index. "gr/eat" --> "gr/eat" // random decision is not to swap the two substrings and keep them in order. "gr/eat" --> "g/r / e/at" // apply the same algorithm recursively on both substrings. divide at ranom index each of them. "g/r / e/at" --> "r/g / e/at" // random decision was to swap the first substring and to keep the second substring in the same order. "r/g / e/at" --> "r/g / e/ a/t" // again apply the algorithm recursively, divide "at" to "a/t". "r/g / e/ a/t" --> "r/g / e/ a/t" // random decision is to keep both substrings in the same order. The algorithm stops now and the result string is "rgeat" which is s2. As there is one possible scenario that led s1 to be scrambled to s2, we return true.
Example 2:
Input: s1 = "abcde", s2 = "caebd"
Output: false
Example 3:
Input: s1 = "a", s2 = "a"
Output: true
Constraints:
s1.length == s2.length
1 <= s1.length <= 30
s1
ands2
consist of lower-case English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Boolean
isScramble(String s1, String s2)
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Method Detail
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isScramble
final Boolean isScramble(String s1, String s2)
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