Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2057 - Smallest Index With Equal Value\.

    Easy

    Given a 0-indexed integer array nums, return the smallest index i of nums such that i mod 10 == nums[i], or -1 if such index does not exist.

    x mod y denotes the remainder when x is divided by y.

    Example 1:

    Input: nums = 0,1,2

    Output: 0

    Explanation:

    i=0: 0 mod 10 = 0 == nums0.

    i=1: 1 mod 10 = 1 == nums1.

    i=2: 2 mod 10 = 2 == nums2.

    All indices have i mod 10 == numsi, so we return the smallest index 0.

    Example 2:

    Input: nums = 4,3,2,1

    Output: 2

    Explanation:

    i=0: 0 mod 10 = 0 != nums0.

    i=1: 1 mod 10 = 1 != nums1.

    i=2: 2 mod 10 = 2 == nums2.

    i=3: 3 mod 10 = 3 != nums3.

    2 is the only index which has i mod 10 == numsi.

    Example 3:

    Input: nums = 1,2,3,4,5,6,7,8,9,0

    Output: -1

    Explanation: No index satisfies i mod 10 == numsi.

    Constraints:

    • 1 <= nums.length <= 100

    • 0 <= nums[i] <= 9

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer smallestEqual(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait