Class Solution
-
- All Implemented Interfaces:
public final class Solution
701 - Insert into a Binary Search Tree.
Medium
You are given the
root
node of a binary search tree (BST) and avalue
to insert into the tree. Return the root node of the BST after the insertion. It is guaranteed that the new value does not exist in the original BST.Notice that there may exist multiple valid ways for the insertion, as long as the tree remains a BST after insertion. You can return any of them.
Example 1:
Input: root = 4,2,7,1,3, val = 5
Output: 4,2,7,1,3,5
Explanation: Another accepted tree is:
Example 2:
Input: root = 40,20,60,10,30,50,70, val = 25
Output: 40,20,60,10,30,50,70,null,null,25
Example 3:
Input: root = 4,2,7,1,3,null,null,null,null,null,null, val = 5
Output: 4,2,7,1,3,5
Constraints:
The number of nodes in the tree will be in the range <code>0, 10<sup>4</sup></code>.
<code>-10<sup>8</sup><= Node.val <= 10<sup>8</sup></code>
All the values
Node.val
are unique.<code>-10<sup>8</sup><= val <= 10<sup>8</sup></code>
It's guaranteed that
val
does not exist in the original BST.
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
Modifier and Type Method Description final TreeNode
insertIntoBST(TreeNode root, Integer value)
-
-
Method Detail
-
insertIntoBST
final TreeNode insertIntoBST(TreeNode root, Integer value)
-
-
-
-