Class Solution

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    public final class Solution
    
                        

    883 - Projection Area of 3D Shapes.

    Easy

    You are given an n x n grid where we place some 1 x 1 x 1 cubes that are axis-aligned with the x, y, and z axes.

    Each value v = grid[i][j] represents a tower of v cubes placed on top of the cell (i, j).

    We view the projection of these cubes onto the xy, yz, and zx planes.

    A projection is like a shadow, that maps our 3-dimensional figure to a 2-dimensional plane. We are viewing the "shadow" when looking at the cubes from the top, the front, and the side.

    Return the total area of all three projections.

    Example 1:

    Input: grid = \[\[1,2],3,4]

    Output: 17

    Explanation: Here are the three projections ("shadows") of the shape made with each axis-aligned plane.

    Example 2:

    Input: grid = \[\[2]]

    Output: 5

    Example 3:

    Input: grid = \[\[1,0],0,2]

    Output: 8

    Constraints:

    • n == grid.length == grid[i].length

    • 1 <= n <= 50

    • 0 <= grid[i][j] <= 50

    • Nested Class Summary

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      Modifier and Type Class Description
    • Field Summary

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    • Constructor Summary

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      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer projectionArea(Array<IntArray> grid)
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        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait