Class Solution
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public final class Solution
1911 - Maximum Alternating Subsequence Sum.
Medium
The alternating sum of a 0-indexed array is defined as the sum of the elements at even indices minus the sum of the elements at odd indices.
For example, the alternating sum of
[4,2,5,3]
is(4 + 5) - (2 + 3) = 4
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Given an array
nums
, return the maximum alternating sum of any subsequence ofnums
(after reindexing the elements of the subsequence).A subsequence of an array is a new array generated from the original array by deleting some elements (possibly none) without changing the remaining elements' relative order. For example,
[2,7,4]
is a subsequence of[4,2,3,7,2,1,4]
(the underlined elements), while[2,4,2]
is not.Example 1:
Input: nums = 4,2,5,3
Output: 7
Explanation: It is optimal to choose the subsequence 4,2,5 with alternating sum (4 + 5) - 2 = 7.
Example 2:
Input: nums = 5,6,7,8
Output: 8
Explanation: It is optimal to choose the subsequence 8 with alternating sum 8.
Example 3:
Input: nums = 6,2,1,2,4,5
Output: 10
Explanation: It is optimal to choose the subsequence 6,1,5 with alternating sum (6 + 5) - 1 = 10.
Constraints:
<code>1 <= nums.length <= 10<sup>5</sup></code>
<code>1 <= numsi<= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Long
maxAlternatingSum(IntArray nums)
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Method Detail
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maxAlternatingSum
final Long maxAlternatingSum(IntArray nums)
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