Class Solution
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- All Implemented Interfaces:
public final class Solution
2092 - Find All People With Secret.
Hard
You are given an integer
n
indicating there aren
people numbered from0
ton - 1
. You are also given a 0-indexed 2D integer arraymeetings
where <code>meetingsi = x<sub>i</sub>, y<sub>i</sub>, time<sub>i</sub></code> indicates that person <code>x<sub>i</sub></code> and person <code>y<sub>i</sub></code> have a meeting at <code>time<sub>i</sub></code>. A person may attend multiple meetings at the same time. Finally, you are given an integerfirstPerson
.Person
0
has a secret and initially shares the secret with a personfirstPerson
at time0
. This secret is then shared every time a meeting takes place with a person that has the secret. More formally, for every meeting, if a person <code>x<sub>i</sub></code> has the secret at <code>time<sub>i</sub></code>, then they will share the secret with person <code>y<sub>i</sub></code>, and vice versa.The secrets are shared instantaneously. That is, a person may receive the secret and share it with people in other meetings within the same time frame.
Return a list of all the people that have the secret after all the meetings have taken place. You may return the answer in any order.
Example 1:
Input: n = 6, meetings = \[\[1,2,5],2,3,8,1,5,10], firstPerson = 1
Output: 0,1,2,3,5
Explanation:
At time 0, person 0 shares the secret with person 1.
At time 5, person 1 shares the secret with person 2.
At time 8, person 2 shares the secret with person 3.
At time 10, person 1 shares the secret with person 5.
Thus, people 0, 1, 2, 3, and 5 know the secret after all the meetings.
Example 2:
Input: n = 4, meetings = \[\[3,1,3],1,2,2,0,3,3], firstPerson = 3
Output: 0,1,3
Explanation:
At time 0, person 0 shares the secret with person 3.
At time 2, neither person 1 nor person 2 know the secret.
At time 3, person 3 shares the secret with person 0 and person 1.
Thus, people 0, 1, and 3 know the secret after all the meetings.
Example 3:
Input: n = 5, meetings = \[\[3,4,2],1,2,1,2,3,1], firstPerson = 1
Output: 0,1,2,3,4
Explanation:
At time 0, person 0 shares the secret with person 1.
At time 1, person 1 shares the secret with person 2, and person 2 shares the secret with person 3.
Note that person 2 can share the secret at the same time as receiving it.
At time 2, person 3 shares the secret with person 4.
Thus, people 0, 1, 2, 3, and 4 know the secret after all the meetings.
Constraints:
<code>2 <= n <= 10<sup>5</sup></code>
<code>1 <= meetings.length <= 10<sup>5</sup></code>
meetings[i].length == 3
<code>0 <= x<sub>i</sub>, y<sub>i</sub><= n - 1</code>
<code>x<sub>i</sub> != y<sub>i</sub></code>
<code>1 <= time<sub>i</sub><= 10<sup>5</sup></code>
1 <= firstPerson <= n - 1
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Constructor Summary
Constructors Constructor Description Solution()
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