Class Solution

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    public final class Solution
    
                        

    2092 - Find All People With Secret.

    Hard

    You are given an integer n indicating there are n people numbered from 0 to n - 1. You are also given a 0-indexed 2D integer array meetings where <code>meetingsi = x<sub>i</sub>, y<sub>i</sub>, time<sub>i</sub></code> indicates that person <code>x<sub>i</sub></code> and person <code>y<sub>i</sub></code> have a meeting at <code>time<sub>i</sub></code>. A person may attend multiple meetings at the same time. Finally, you are given an integer firstPerson.

    Person 0 has a secret and initially shares the secret with a person firstPerson at time 0. This secret is then shared every time a meeting takes place with a person that has the secret. More formally, for every meeting, if a person <code>x<sub>i</sub></code> has the secret at <code>time<sub>i</sub></code>, then they will share the secret with person <code>y<sub>i</sub></code>, and vice versa.

    The secrets are shared instantaneously. That is, a person may receive the secret and share it with people in other meetings within the same time frame.

    Return a list of all the people that have the secret after all the meetings have taken place. You may return the answer in any order.

    Example 1:

    Input: n = 6, meetings = \[\[1,2,5],2,3,8,1,5,10], firstPerson = 1

    Output: 0,1,2,3,5

    Explanation:

    At time 0, person 0 shares the secret with person 1.

    At time 5, person 1 shares the secret with person 2.

    At time 8, person 2 shares the secret with person 3.

    At time 10, person 1 shares the secret with person 5.

    Thus, people 0, 1, 2, 3, and 5 know the secret after all the meetings.

    Example 2:

    Input: n = 4, meetings = \[\[3,1,3],1,2,2,0,3,3], firstPerson = 3

    Output: 0,1,3

    Explanation:

    At time 0, person 0 shares the secret with person 3.

    At time 2, neither person 1 nor person 2 know the secret.

    At time 3, person 3 shares the secret with person 0 and person 1.

    Thus, people 0, 1, and 3 know the secret after all the meetings.

    Example 3:

    Input: n = 5, meetings = \[\[3,4,2],1,2,1,2,3,1], firstPerson = 1

    Output: 0,1,2,3,4

    Explanation:

    At time 0, person 0 shares the secret with person 1.

    At time 1, person 1 shares the secret with person 2, and person 2 shares the secret with person 3.

    Note that person 2 can share the secret at the same time as receiving it.

    At time 2, person 3 shares the secret with person 4.

    Thus, people 0, 1, 2, 3, and 4 know the secret after all the meetings.

    Constraints:

    • <code>2 <= n <= 10<sup>5</sup></code>

    • <code>1 <= meetings.length <= 10<sup>5</sup></code>

    • meetings[i].length == 3

    • <code>0 <= x<sub>i</sub>, y<sub>i</sub><= n - 1</code>

    • <code>x<sub>i</sub> != y<sub>i</sub></code>

    • <code>1 <= time<sub>i</sub><= 10<sup>5</sup></code>

    • 1 &lt;= firstPerson &lt;= n - 1

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final List<Integer> findAllPeople(Integer n, Array<IntArray> meetings, Integer firstPerson)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait