Class Solution
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public final class Solution
1846 - Maximum Element After Decreasing and Rearranging.
Medium
You are given an array of positive integers
arr
. Perform some operations (possibly none) onarr
so that it satisfies these conditions:The value of the first element in
arr
must be1
.The absolute difference between any 2 adjacent elements must be less than or equal to
1
. In other words,abs(arr[i] - arr[i - 1]) <= 1
for eachi
where1 <= i < arr.length
( 0-indexed ).abs(x)
is the absolute value ofx
.
There are 2 types of operations that you can perform any number of times:
Decrease the value of any element of
arr
to a smaller positive integer.Rearrange the elements of
arr
to be in any order.
Return the maximum possible value of an element in
arr
after performing the operations to satisfy the conditions.Example 1:
Input: arr = 2,2,1,2,1
Output: 2
Explanation:
We can satisfy the conditions by rearranging
arr
so it becomes[1,2,2,2,1]
.The largest element in
arr
is 2.Example 2:
Input: arr = 100,1,1000
Output: 3
Explanation:
One possible way to satisfy the conditions is by doing the following:
Rearrange
arr
so it becomes[1,100,1000]
.Decrease the value of the second element to 2.
Decrease the value of the third element to 3.
Now
arr = [1,2,3], which
satisfies the conditions.The largest element in
arr is 3.
Example 3:
Input: arr = 1,2,3,4,5
Output: 5
Explanation: The array already satisfies the conditions, and the largest element is 5.
Constraints:
<code>1 <= arr.length <= 10<sup>5</sup></code>
<code>1 <= arri<= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
maximumElementAfterDecrementingAndRearranging(IntArray arr)
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Method Detail
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maximumElementAfterDecrementingAndRearranging
final Integer maximumElementAfterDecrementingAndRearranging(IntArray arr)
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