2933 - High-Access Employees.

Medium

You are given a 2D 0-indexed array of strings, access_times, with size n. For each i where 0 <= i <= n - 1, access_times[i][0] represents the name of an employee, and access_times[i][1] represents the access time of that employee. All entries in access_times are within the same day.

The access time is represented as four digits using a 24-hour time format, for example, "0800" or "2250".

An employee is said to be high-access if he has accessed the system three or more times within a one-hour period.

Times with exactly one hour of difference are not considered part of the same one-hour period. For example, "0815" and "0915" are not part of the same one-hour period.

Access times at the start and end of the day are not counted within the same one-hour period. For example, "0005" and "2350" are not part of the same one-hour period.

Return a list that contains the names of high-access employees with any order you want.

Example 1:

Input: access\_times = \[\["a","0549"],"b","0457","a","0532","a","0621","b","0540"]

Output: "a"

Explanation: "a" has three access times in the one-hour period of 05:32, 06:31 which are 05:32, 05:49, and 06:21. But "b" does not have more than two access times at all. So the answer is "a".

Example 2:

Input: access\_times = \[\["d","0002"],"c","0808","c","0829","e","0215","d","1508","d","1444","d","1410","c","0809"]

Output: "c","d"

Explanation: "c" has three access times in the one-hour period of 08:08, 09:07 which are 08:08, 08:09, and 08:29. "d" has also three access times in the one-hour period of 14:10, 15:09 which are 14:10, 14:44, and 15:08. However, "e" has just one access time, so it can not be in the answer and the final answer is "c","d".

Example 3:

Input: access\_times = \[\["cd","1025"],"ab","1025","cd","1046","cd","1055","ab","1124","ab","1120"]

Output: "ab","cd"

Explanation: "ab" has three access times in the one-hour period of 10:25, 11:24 which are 10:25, 11:20, and 11:24. "cd" has also three access times in the one-hour period of 10:25, 11:24 which are 10:25, 10:46, and 10:55. So the answer is "ab","cd".

Constraints:

• 1 <= access_times.length <= 100

• access_times[i].length == 2

• 1 <= access_times[i][0].length <= 10

• access_times[i][0] consists only of English small letters.

• access_times[i][1].length == 4

• access_times[i][1] is in 24-hour time format.

• access_times[i][1] consists only of '0' to '9'.