Class Solution
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public final class Solution
2331 - Evaluate Boolean Binary Tree.
Easy
You are given the
root
of a full binary tree with the following properties:Leaf nodes have either the value
0
or1
, where0
representsFalse
and1
representsTrue
.Non-leaf nodes have either the value
2
or3
, where2
represents the booleanOR
and3
represents the booleanAND
.
The evaluation of a node is as follows:
If the node is a leaf node, the evaluation is the value of the node, i.e.
True
orFalse
.Otherwise, evaluate the node's two children and apply the boolean operation of its value with the children's evaluations.
Return the boolean result of evaluating the
root
node.A full binary tree is a binary tree where each node has either
0
or2
children.A leaf node is a node that has zero children.
Example 1:
Input: root = 2,1,3,null,null,0,1
Output: true
Explanation: The above diagram illustrates the evaluation process.
The AND node evaluates to False AND True = False.
The OR node evaluates to True OR False = True.
The root node evaluates to True, so we return true.
Example 2:
Input: root = 0
Output: false
Explanation: The root node is a leaf node and it evaluates to false, so we return false.
Constraints:
The number of nodes in the tree is in the range
[1, 1000]
.0 <= Node.val <= 3
Every node has either
0
or2
children.Leaf nodes have a value of
0
or1
.Non-leaf nodes have a value of
2
or3
.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Boolean
evaluateTree(TreeNode root)
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Method Detail
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evaluateTree
final Boolean evaluateTree(TreeNode root)
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