Package g0201_0300.s0290_word_pattern
Class Solution
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public final class Solution
290 - Word Pattern.
Easy
Given a
pattern
and a strings
, find ifs
follows the same pattern.Here follow means a full match, such that there is a bijection between a letter in
pattern
and a non-empty word ins
.Example 1:
Input: pattern = "abba", s = "dog cat cat dog"
Output: true
Example 2:
Input: pattern = "abba", s = "dog cat cat fish"
Output: false
Example 3:
Input: pattern = "aaaa", s = "dog cat cat dog"
Output: false
Constraints:
1 <= pattern.length <= 300
pattern
contains only lower-case English letters.1 <= s.length <= 3000
s
contains only lowercase English letters and spaces' '
.s
does not contain any leading or trailing spaces.All the words in
s
are separated by a single space.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Boolean
wordPattern(String pattern, String s)
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Method Detail
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wordPattern
final Boolean wordPattern(String pattern, String s)
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