Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    791 - Custom Sort String.

    Medium

    You are given two strings order and s. All the words of order are unique and were sorted in some custom order previously.

    Permute the characters of s so that they match the order that order was sorted. More specifically, if a character x occurs before a character y in order, then x should occur before y in the permuted string.

    Return any permutation of s that satisfies this property.

    Example 1:

    Input: order = "cba", s = "abcd"

    Output: "cbad"

    Explanation: "a", "b", "c" appear in order, so the order of "a", "b", "c" should be "c", "b", and "a". Since "d" does not appear in order, it can be at any position in the returned string. "dcba", "cdba", "cbda" are also valid outputs.

    Example 2:

    Input: order = "cbafg", s = "abcd"

    Output: "cbad"

    Constraints:

    • 1 <= order.length <= 26

    • 1 <= s.length <= 200

    • order and s consist of lowercase English letters.

    • All the characters of order are unique.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final String customSortString(String order, String s)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait