Class Solution
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public final class Solution
1680 - Concatenation of Consecutive Binary Numbers.
Medium
Given an integer
n
, return the decimal value of the binary string formed by concatenating the binary representations of1
ton
in order, modulo <code>10<sup>9</sup> + 7</code>.Example 1:
Input: n = 1
Output: 1
Explanation: "1" in binary corresponds to the decimal value 1.
Example 2:
Input: n = 3
Output: 27
Explanation: In binary, 1, 2, and 3 corresponds to "1", "10", and "11".
After concatenating them, we have "11011", which corresponds to the decimal value 27.
Example 3:
Input: n = 12
Output: 505379714
Explanation: The concatenation results in "1101110010111011110001001101010111100".
The decimal value of that is 118505380540.
After modulo 10<sup>9</sup> + 7, the result is 505379714.
Constraints:
<code>1 <= n <= 10<sup>5</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
concatenatedBinary(Integer n)
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Method Detail
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concatenatedBinary
final Integer concatenatedBinary(Integer n)
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