Class Solution
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public final class Solution
2344 - Minimum Deletions to Make Array Divisible.
Hard
You are given two positive integer arrays
nums
andnumsDivide
. You can delete any number of elements fromnums
.Return the minimum number of deletions such that the smallest element in
nums
divides all the elements ofnumsDivide
. If this is not possible, return-1
.Note that an integer
x
dividesy
ify % x == 0
.Example 1:
Input: nums = 2,3,2,4,3, numsDivide = 9,6,9,3,15
Output: 2
Explanation:
The smallest element in 2,3,2,4,3 is 2, which does not divide all the elements of numsDivide.
We use 2 deletions to delete the elements in nums that are equal to 2 which makes nums = 3,4,3.
The smallest element in 3,4,3 is 3, which divides all the elements of numsDivide.
It can be shown that 2 is the minimum number of deletions needed.
Example 2:
Input: nums = 4,3,6, numsDivide = 8,2,6,10
Output: -1
Explanation:
We want the smallest element in nums to divide all the elements of numsDivide.
There is no way to delete elements from nums to allow this.
Constraints:
<code>1 <= nums.length, numsDivide.length <= 10<sup>5</sup></code>
<code>1 <= numsi, numsDividei<= 10<sup>9</sup></code>
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
minOperations(IntArray nums, IntArray numsDivide)
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Method Detail
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minOperations
final Integer minOperations(IntArray nums, IntArray numsDivide)
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