Class Solution
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public final class Solution
2643 - Row With Maximum Ones.
Easy
Given a
m x n
binary matrixmat
, find the 0-indexed position of the row that contains the maximum count of **ones, ** and the number of ones in that row.In case there are multiple rows that have the maximum count of ones, the row with the smallest row number should be selected.
Return an array containing the index of the row, and the number of ones in it.
Example 1:
Input: mat = [0,1,1,0]
Output: 0,1
Explanation: Both rows have the same number of 1's. So we return the index of the smaller row, 0, and the maximum count of ones (1
)
. So, the answer is 0,1.Example 2:
Input: mat = [0,0,0,0,1,1]
Output: 1,2
Explanation: The row indexed 1 has the maximum count of ones
(2)
. So we return its index,1
, and the count. So, the answer is 1,2.Example 3:
Input: mat = [0,0,1,1,0,0]
Output: 1,2
Explanation: The row indexed 1 has the maximum count of ones (2). So the answer is 1,2.
Constraints:
m == mat.length
n == mat[i].length
1 <= m, n <= 100
mat[i][j]
is either0
or1
.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntArray
rowAndMaximumOnes(Array<IntArray> mat)
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Method Detail
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rowAndMaximumOnes
final IntArray rowAndMaximumOnes(Array<IntArray> mat)
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