Class Solution
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- All Implemented Interfaces:
public final class Solution
112 - Path Sum.
Easy
Given the
root
of a binary tree and an integertargetSum
, returntrue
if the tree has a root-to-leaf path such that adding up all the values along the path equalstargetSum
.A leaf is a node with no children.
Example 1:
Input: root = 5,4,8,11,null,13,4,7,2,null,null,null,1, targetSum = 22
Output: true
Explanation: The root-to-leaf path with the target sum is shown.
Example 2:
Input: root = 1,2,3, targetSum = 5
Output: false
Explanation: There two root-to-leaf paths in the tree:
(1 --> 2): The sum is 3.
(1 --> 3): The sum is 4.
There is no root-to-leaf path with sum = 5.
Example 3:
Input: root = [], targetSum = 0
Output: false
Explanation: Since the tree is empty, there are no root-to-leaf paths.
Constraints:
The number of nodes in the tree is in the range
[0, 5000]
.-1000 <= Node.val <= 1000
-1000 <= targetSum <= 1000
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Boolean
hasPathSum(TreeNode root, Integer targetSum)
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Method Detail
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hasPathSum
final Boolean hasPathSum(TreeNode root, Integer targetSum)
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