Class Solution
-
- All Implemented Interfaces:
public final class Solution
994 - Rotting Oranges.
Medium
You are given an
m x n
grid
where each cell can have one of three values:0
representing an empty cell,1
representing a fresh orange, or2
representing a rotten orange.
Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.
Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return
-1
.Example 1:
Input: grid = [2,1,1,1,1,0,0,1,1]
Output: 4
Example 2:
Input: grid = [2,1,1,0,1,1,1,0,1]
Output: -1
Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.
Example 3:
Input: grid = [0,2]
Output: 0
Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.
Constraints:
m == grid.length
n == grid[i].length
1 <= m, n <= 10
grid[i][j]
is0
,1
, or2
.
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
Modifier and Type Method Description final Integer
orangesRotting(Array<IntArray> grid)
-
-
Method Detail
-
orangesRotting
final Integer orangesRotting(Array<IntArray> grid)
-
-
-
-