Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    994 - Rotting Oranges.

    Medium

    You are given an m x n grid where each cell can have one of three values:

    • 0 representing an empty cell,

    • 1 representing a fresh orange, or

    • 2 representing a rotten orange.

    Every minute, any fresh orange that is 4-directionally adjacent to a rotten orange becomes rotten.

    Return the minimum number of minutes that must elapse until no cell has a fresh orange. If this is impossible, return -1.

    Example 1:

    Input: grid = [2,1,1,1,1,0,0,1,1]

    Output: 4

    Example 2:

    Input: grid = [2,1,1,0,1,1,1,0,1]

    Output: -1

    Explanation: The orange in the bottom left corner (row 2, column 0) is never rotten, because rotting only happens 4-directionally.

    Example 3:

    Input: grid = [0,2]

    Output: 0

    Explanation: Since there are already no fresh oranges at minute 0, the answer is just 0.

    Constraints:

    • m == grid.length

    • n == grid[i].length

    • 1 <= m, n <= 10

    • grid[i][j] is 0, 1, or 2.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer orangesRotting(Array<IntArray> grid)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait