Class Solution

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    public final class Solution
    
                        

    1235 - Maximum Profit in Job Scheduling.

    Hard

    We have n jobs, where every job is scheduled to be done from startTime[i] to endTime[i], obtaining a profit of profit[i].

    You're given the startTime, endTime and profit arrays, return the maximum profit you can take such that there are no two jobs in the subset with overlapping time range.

    If you choose a job that ends at time X you will be able to start another job that starts at time X.

    Example 1:

    Input: startTime = 1,2,3,3, endTime = 3,4,5,6, profit = 50,10,40,70

    Output: 120

    Explanation: The subset chosen is the first and fourth job. Time range 1-3+3-6 , we get profit of 120 = 50 + 70.

    Example 2:

    Input: startTime = 1,2,3,4,6, endTime = 3,5,10,6,9, profit = 20,20,100,70,60

    Output: 150

    Explanation: The subset chosen is the first, fourth and fifth job. Profit obtained 150 = 20 + 70 + 60.

    Example 3:

    Input: startTime = 1,1,1, endTime = 2,3,4, profit = 5,6,4

    Output: 6

    Constraints:

    • <code>1 <= startTime.length == endTime.length == profit.length <= 5 * 10<sup>4</sup></code>

    • <code>1 <= startTimei< endTimei<= 10<sup>9</sup></code>

    • <code>1 <= profiti<= 10<sup>4</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer jobScheduling(IntArray startTime, IntArray endTime, IntArray profit)
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        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait