Class Solution
-
- All Implemented Interfaces:
public final class Solution
1652 - Defuse the Bomb.
Easy
You have a bomb to defuse, and your time is running out! Your informer will provide you with a circular array
code
of length ofn
and a keyk
.To decrypt the code, you must replace every number. All the numbers are replaced simultaneously.
If
k > 0
, replace the <code>i<sup>th</sup></code> number with the sum of the nextk
numbers.If
k < 0
, replace the <code>i<sup>th</sup></code> number with the sum of the previousk
numbers.If
k == 0
, replace the <code>i<sup>th</sup></code> number with0
.
As
code
is circular, the next element ofcode[n-1]
iscode[0]
, and the previous element ofcode[0]
iscode[n-1]
.Given the circular array
code
and an integer keyk
, return the decrypted code to defuse the bomb!Example 1:
Input: code = 5,7,1,4, k = 3
Output: 12,10,16,13
Explanation: Each number is replaced by the sum of the next 3 numbers. The decrypted code is 7+1+4, 1+4+5, 4+5+7, 5+7+1. Notice that the numbers wrap around.
Example 2:
Input: code = 1,2,3,4, k = 0
Output: 0,0,0,0
Explanation: When k is zero, the numbers are replaced by 0.
Example 3:
Input: code = 2,4,9,3, k = -2
Output: 12,5,6,13
Explanation: The decrypted code is 3+9, 2+3, 4+2, 9+4. Notice that the numbers wrap around again. If k is negative, the sum is of the previous numbers.
Constraints:
n == code.length
1 <= n <= 100
1 <= code[i] <= 100
-(n - 1) <= k <= n - 1
-
-
Constructor Summary
Constructors Constructor Description Solution()
-