Package g2501_2600.s2562_find_the_array_concatenation_value

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    2562 - Find the Array Concatenation Value.

    Easy

    You are given a 0-indexed integer array nums.

    The concatenation of two numbers is the number formed by concatenating their numerals.

    • For example, the concatenation of 15, 49 is 1549.

    The concatenation value of nums is initially equal to 0. Perform this operation until nums becomes empty:

    • If there exists more than one number in nums, pick the first element and last element in nums respectively and add the value of their concatenation to the concatenation value of nums, then delete the first and last element from nums.

    • If one element exists, add its value to the concatenation value of nums, then delete it.

    Return the concatenation value of the nums.

    Example 1:

    Input: nums = 7,52,2,4

    Output: 596

    Explanation: Before performing any operation, nums is 7,52,2,4 and concatenation value is 0.

    • In the first operation: We pick the first element, 7, and the last element, 4. Their concatenation is 74, and we add it to the concatenation value, so it becomes equal to 74. Then we delete them from nums, so nums becomes equal to 52,2.

    • In the second operation: We pick the first element, 52, and the last element, 2. Their concatenation is 522, and we add it to the concatenation value, so it becomes equal to 596. Then we delete them from the nums, so nums becomes empty. Since the concatenation value is 596 so the answer is 596.

    Example 2:

    Input: nums = 5,14,13,8,12

    Output: 673

    Explanation: Before performing any operation, nums is 5,14,13,8,12 and concatenation value is 0.

    • In the first operation: We pick the first element, 5, and the last element, 12. Their concatenation is 512, and we add it to the concatenation value, so it becomes equal to 512. Then we delete them from the nums, so nums becomes equal to 14,13,8.

    • In the second operation: We pick the first element, 14, and the last element, 8. Their concatenation is 148, and we add it to the concatenation value, so it becomes equal to 660. Then we delete them from the nums, so nums becomes equal to 13.

    • In the third operation: nums has only one element, so we pick 13 and add it to the concatenation value, so it becomes equal to 673. Then we delete it from nums, so nums become empty. Since the concatenation value is 673 so the answer is 673.

    Constraints:

    • 1 <= nums.length <= 1000

    • <code>1 <= numsi<= 10<sup>4</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description

    • Field Summary

      Fields 
      Modifier and Type Field Description

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final Long findTheArrayConcVal(IntArray nums)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait