Class Solution
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public final class Solution
2760 - Longest Even Odd Subarray With Threshold.
Easy
You are given a 0-indexed integer array
nums
and an integerthreshold
.Find the length of the longest subarray of
nums
starting at indexl
and ending at indexr
(0 <= l <= r < nums.length)
that satisfies the following conditions:nums[l] % 2 == 0
For all indices
i
in the range[l, r - 1]
,nums[i] % 2 != nums[i + 1] % 2
For all indices
i
in the range[l, r]
,nums[i] <= threshold
Return an integer denoting the length of the longest such subarray.
Note: A subarray is a contiguous non-empty sequence of elements within an array.
Example 1:
Input: nums = 3,2,5,4, threshold = 5
Output: 3
Explanation:
In this example, we can select the subarray that starts at l = 1 and ends at r = 3 =>2,5,4. This subarray satisfies the conditions.
Hence, the answer is the length of the subarray, 3. We can show that 3 is the maximum possible achievable length.
Example 2:
Input: nums = 1,2, threshold = 2
Output: 1
Explanation:
In this example, we can select the subarray that starts at l = 1 and ends at r = 1 =>2.
It satisfies all the conditions and we can show that 1 is the maximum possible achievable length.
Example 3:
Input: nums = 2,3,4,5, threshold = 4
Output: 3
Explanation:
In this example, we can select the subarray that starts at l = 0 and ends at r = 2 =>2,3,4.
It satisfies all the conditions. Hence, the answer is the length of the subarray, 3. We can show that 3 is the maximum possible achievable length.
Constraints:
1 <= nums.length <= 100
1 <= nums[i] <= 100
1 <= threshold <= 100
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
longestAlternatingSubarray(IntArray nums, Integer threshold)
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Method Detail
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longestAlternatingSubarray
final Integer longestAlternatingSubarray(IntArray nums, Integer threshold)
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