Class Solution
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public final class Solution
3498 - Reverse Degree of a String.
Easy
Given a string
s
, calculate its reverse degree.The reverse degree is calculated as follows:
For each character, multiply its position in the reversed alphabet (
'a'
= 26,'b'
= 25, ...,'z'
= 1) with its position in the string (1-indexed).Sum these products for all characters in the string.
Return the reverse degree of
s
.Example 1:
Input: s = "abc"
Output: 148
Explanation:
The reversed degree is
26 + 50 + 72 = 148
.Example 2:
Input: s = "zaza"
Output: 160
Explanation:
The reverse degree is
1 + 52 + 3 + 104 = 160
.Constraints:
1 <= s.length <= 1000
s
contains only lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final Integer
reverseDegree(String s)
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Method Detail
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reverseDegree
final Integer reverseDegree(String s)
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