Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2595 - Number of Even and Odd Bits.

    Easy

    You are given a positive integer n.

    Let even denote the number of even indices in the binary representation of n ( 0-indexed ) with value 1.

    Let odd denote the number of odd indices in the binary representation of n ( 0-indexed ) with value 1.

    Return an integer array answer where answer = [even, odd].

    Example 1:

    Input: n = 17

    Output: 2,0

    Explanation:

    The binary representation of 17 is 10001.

    It contains 1 on the 0<sup>th</sup> and 4<sup>th</sup> indices.

    There are 2 even and 0 odd indices.

    Example 2:

    Input: n = 2

    Output: 0,1

    Explanation:

    The binary representation of 2 is 10.

    It contains 1 on the 1<sup>st</sup> index.

    There are 0 even and 1 odd indices.

    Constraints:

    • 1 &lt;= n &lt;= 1000

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final IntArray evenOddBit(Integer n)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait