Class Solution

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    public final class Solution
    
                        

    3583 - Count Special Triplets.

    Medium

    You are given an integer array nums.

    A special triplet is defined as a triplet of indices (i, j, k) such that:

    • 0 <= i < j < k < n, where n = nums.length

    • nums[i] == nums[j] * 2

    • nums[k] == nums[j] * 2

    Return the total number of special triplets in the array.

    Since the answer may be large, return it modulo <code>10<sup>9</sup> + 7</code>.

    Example 1:

    Input: nums = 6,3,6

    Output: 1

    Explanation:

    The only special triplet is (i, j, k) = (0, 1, 2), where:

    • nums[0] = 6, nums[1] = 3, nums[2] = 6

    • nums[0] = nums[1] * 2 = 3 * 2 = 6

    • nums[2] = nums[1] * 2 = 3 * 2 = 6

    Example 2:

    Input: nums = 0,1,0,0

    Output: 1

    Explanation:

    The only special triplet is (i, j, k) = (0, 2, 3), where:

    • nums[0] = 0, nums[2] = 0, nums[3] = 0

    • nums[0] = nums[2] * 2 = 0 * 2 = 0

    • nums[3] = nums[2] * 2 = 0 * 2 = 0

    Example 3:

    Input: nums = 8,4,2,8,4

    Output: 2

    Explanation:

    There are exactly two special triplets:

    • (i, j, k) = (0, 1, 3)

    • (i, j, k) = (1, 2, 4)

    Constraints:

    • <code>3 <= n == nums.length <= 10<sup>5</sup></code>

    • <code>0 <= numsi<= 10<sup>5</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer specialTriplets(IntArray nums)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait