Class RewriteAsyncIteration
- All Implemented Interfaces:
CompilerPass
,NodeTraversal.Callback
async function* foo() {
let res = await myPromise;
yield res + 1;
}
becomes (prefixes trimmed for clarity)
function foo() {
return new $jscomp.AsyncGeneratorWrapper((function*(){
let res = yield new $ActionRecord($ActionEnum.AWAIT_VALUE, myPromise);
yield new $ActionRecord($ActionEnum.YIELD_VALUE, res + 1);
})());
}
-
Method Summary
Modifier and TypeMethodDescriptionvoid
Process the JS with root node root.boolean
shouldTraverse
(NodeTraversal nodeTraversal, Node n, Node parent) Visits a node in preorder (before its children) and decides whether the node and its children should be traversed.void
visit
(NodeTraversal t, Node n, Node parent) Visits a node in postorder (after its children).
-
Method Details
-
process
Description copied from interface:CompilerPass
Process the JS with root node root. Can modify the contents of each Node tree- Specified by:
process
in interfaceCompilerPass
- Parameters:
externs
- Top of external JS treeroot
- Top of JS tree
-
shouldTraverse
Description copied from interface:NodeTraversal.Callback
Visits a node in preorder (before its children) and decides whether the node and its children should be traversed.If this method returns true, the node will be visited by
NodeTraversal.Callback.visit(NodeTraversal, Node, Node)
in postorder and its children will be visited by bothNodeTraversal.Callback.shouldTraverse(NodeTraversal, Node, Node)
in preorder and byNodeTraversal.Callback.visit(NodeTraversal, Node, Node)
in postorder.If this method returns false, the node will not be visited by
NodeTraversal.Callback.visit(NodeTraversal, Node, Node)
and its children will neither be visited byNodeTraversal.Callback.shouldTraverse(NodeTraversal, Node, Node)
norNodeTraversal.Callback.visit(NodeTraversal, Node, Node)
.Siblings are always visited left-to-right.
Implementations can have side-effects (e.g. modify the parse tree). Removing the current node is legal, but removing or reordering nodes above the current node may cause nodes to be visited twice or not at all.
- Specified by:
shouldTraverse
in interfaceNodeTraversal.Callback
- Parameters:
nodeTraversal
- The current traversal.n
- The current node.parent
- The parent of the current node.- Returns:
- whether the children of this node should be visited
-
visit
Description copied from interface:NodeTraversal.Callback
Visits a node in postorder (after its children). A node is visited in postorder iffNodeTraversal.Callback.shouldTraverse(NodeTraversal, Node, Node)
returned true for its parent and itself. In particular, the root node is never visited in postorder.Siblings are always visited left-to-right.
Implementations can have side-effects (e.g. modify the parse tree). Removing the current node is legal, but removing or reordering nodes above the current node may cause nodes to be visited twice or not at all.
- Specified by:
visit
in interfaceNodeTraversal.Callback
- Parameters:
t
- The current traversal.n
- The current node.parent
- The parent of the current node.
-