com.outworkers.phantom.dsl

MapKeyConditionals

implicit final class MapKeyConditionals[T <: CassandraTable[T, R], R, K, V] extends AnyVal

Definition used to cast an index map column with keys indexed to a query-able definition. This will allow users to use "CONTAINS KEY" clauses to search for matches based on map keys.

T

The Cassandra table inner type.

R

The record type of the table.

K

The type of the key held in the map.

V

The type of the value held in the map.

returns

A MapConditionals class with CONTAINS KEY support.

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Instance Constructors

  1. new MapKeyConditionals(col: AbstractMapColumn[T, R, K, V] with Indexed with Keys)

    col

    The map column to cast to a Map column secondary index query.

Value Members

  1. final def !=(arg0: Any): Boolean

    Definition Classes
    Any
  2. final def ##(): Int

    Definition Classes
    Any
  3. final def ==(arg0: Any): Boolean

    Definition Classes
    Any
  4. final def asInstanceOf[T0]: T0

    Definition Classes
    Any
  5. val col: AbstractMapColumn[T, R, K, V] with Indexed with Keys

    The map column to cast to a Map column secondary index query.

  6. final def containsKey(elem: K): builder.clauses.WhereClause.Condition

    Generates a Map CONTAINS KEY clause that can be used inside a CQL Where condition.

    Generates a Map CONTAINS KEY clause that can be used inside a CQL Where condition. This allows users to lookup records by a KEY inside a map column of a table.

    Key support is not yet enabled in phantom because index generation has to be done differently. Otherwise, there is no support for simultaneous indexing on both KEYS and VALUES of a MAP column. This limitation will be lifted in the future.

    elem

    The element to check for in the contains clause.

    returns

    A Where clause.

  7. def getClass(): Class[_ <: AnyVal]

    Definition Classes
    AnyVal → Any
  8. final def isInstanceOf[T0]: Boolean

    Definition Classes
    Any
  9. def toString(): String

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Inherited from AnyVal

Inherited from NotNull

Inherited from Any

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