Class

io.epiphanous.flinkrunner.util.StreamUtils

Pipe

Related Doc: package StreamUtils

Permalink

implicit final class Pipe[A] extends AnyVal

A little syntactic sugar for writing stream program. This is the pipe operator, ala F#.

Assuming

source

This let's us write

def program:DataStream[E] = source |> transform |# sink

instead of

def program:DataStream[E] = {
  val result:DataStream[E] = transform(source)
  sink(result)
  result
}

source }}}

def program:DataStream[E] = source |> transform |# sink

instead of

def program:DataStream[E] = {
  val result:DataStream[E] = transform(source)
  sink(result)
  result
}
A

the type of v

Linear Supertypes
AnyVal, Any
Ordering
  1. Alphabetic
  2. By Inheritance
Inherited
  1. Pipe
  2. AnyVal
  3. Any
  1. Hide All
  2. Show All
Visibility
  1. Public
  2. All

Instance Constructors

  1. new Pipe(v: A)

    Permalink

    v

    any object

Value Members

  1. final def !=(arg0: Any): Boolean

    Permalink
    Definition Classes
    Any
  2. final def ##(): Int

    Permalink
    Definition Classes
    Any
  3. final def ==(arg0: Any): Boolean

    Permalink
    Definition Classes
    Any
  4. final def asInstanceOf[T0]: T0

    Permalink
    Definition Classes
    Any
  5. def getClass(): Class[_ <: AnyVal]

    Permalink
    Definition Classes
    AnyVal → Any
  6. final def isInstanceOf[T0]: Boolean

    Permalink
    Definition Classes
    Any
  7. def toString(): String

    Permalink
    Definition Classes
    Any
  8. val v: A

    Permalink

    any object

  9. def |#(e: (A) ⇒ Unit): A

    Permalink
  10. def |>[B](t: (A) ⇒ B): B

    Permalink

Inherited from AnyVal

Inherited from Any

Ungrouped