scala

Function1

trait Function1[-T1, +R] extends AnyRef

Function with 1 parameter.

In the following example the definition of `succ` is a shorthand for the anonymous class definition `anonfun1`:

``` object Main extends Application {   val succ = (x: Int) => x + 1   val anonfun1 = new Function1[Int, Int] {
def apply(x: Int): Int = x + 1
}   println(succ(0))
println(anonfun1(0))
}```

1. AnyRef
2. Any

Value Members

1. def andThen[A](g: (R) ⇒ A): (T1) ⇒ A

(f andThen g)(x) == g(f(x))

(f andThen g)(x) == g(f(x))

3. def compose[A](g: (A) ⇒ T1): (A) ⇒ R

(f compose g)(x) == f(g(x))

(f compose g)(x) == f(g(x))

4. def equals(arg0: Any): Boolean

This method is used to compare the receiver object (`this`) with the argument object (`arg0`) for equivalence

This method is used to compare the receiver object (`this`) with the argument object (`arg0`) for equivalence.

The default implementations of this method is an equivalence relation:

• It is reflexive: for any instance `x` of type `Any`, `x.equals(x)` should return `true`.
• It is symmetric: for any instances `x` and `y` of type `Any`, `x.equals(y)` should return `true` if and only if `y.equals(x)` returns `true`.
• It is transitive: for any instances `x`, `y`, and `z` of type `AnyRef` if `x.equals(y)` returns `true` and `y.equals(z)` returns `true`, then `x.equals(z)` should return `true`.

If you override this method, you should verify that your implementation remains an equivalence relation. Additionally, when overriding this method it is often necessary to override `hashCode` to ensure that objects that are "equal" (`o1.equals(o2)` returns `true`) hash to the same `Int` (`o1.hashCode.equals(o2.hashCode)`).

arg0

the object to compare against this object for equality.

returns

`true` if the receiver object is equivalent to the argument; `false` otherwise.

definition classes: AnyRef ⇐ Any
5. def hashCode(): Int

Returns a hash code value for the object

Returns a hash code value for the object.

The default hashing algorithm is platform dependent.

Note that it is allowed for two objects to have identical hash codes (`o1.hashCode.equals(o2.hashCode)`) yet not be equal (`o1.equals(o2)` returns `false`). A degenerate implementation could always return `0`. However, it is required that if two objects are equal (`o1.equals(o2)` returns `true`) that they have identical hash codes (`o1.hashCode.equals(o2.hashCode)`). Therefore, when overriding this method, be sure to verify that the behavior is consistent with the `equals` method.

definition classes: AnyRef ⇐ Any
6. def toString(): String

Returns a string representation of the object

Returns a string representation of the object.

The default representation is platform dependent.