final class Using[A] extends AnyVal
Helper for syntactic sugar of js.use. Only use in js.use(x).as[T]
Linear Supertypes
Ordering
- Alphabetic
- By Inheritance
Inherited
- Using
- AnyVal
- Any
Implicitly
- by any2stringadd
- by StringFormat
- by Ensuring
- by ArrowAssoc
- Hide All
- Show All
Visibility
- Public
- Protected
Value Members
- final def !=(arg0: scala.Any): Boolean
- Definition Classes
- Any
- final def ##: Int
- Definition Classes
- Any
- def +(other: String): String
- def ->[B](y: B): (Using[A], B)
- final def ==(arg0: scala.Any): Boolean
- Definition Classes
- Any
- macro def as[B <: Any]: B
- final def asInstanceOf[T0]: T0
- Definition Classes
- Any
- def ensuring(cond: (Using[A]) => Boolean, msg: => scala.Any): Using[A]
- def ensuring(cond: (Using[A]) => Boolean): Using[A]
- def ensuring(cond: Boolean, msg: => scala.Any): Using[A]
- def ensuring(cond: Boolean): Using[A]
- def formatted(fmtstr: String): String
- def getClass(): Class[_ <: AnyVal]
- Definition Classes
- AnyVal → Any
- final def isInstanceOf[T0]: Boolean
- Definition Classes
- Any
- def toString(): String
- Definition Classes
- Any
- val x: A
Deprecated Value Members
- def →[B](y: B): (Using[A], B)
- Implicit
- This member is added by an implicit conversion from Using[A] toArrowAssoc[Using[A]] performed by method ArrowAssoc in scala.Predef.
- Definition Classes
- ArrowAssoc
- Annotations
- @deprecated
- Deprecated
(Since version 2.13.0) Use
->instead. If you still wish to display it as one character, consider using a font with programming ligatures such as Fira Code.