object pilib extends AnyRef

Library for using Pi-calculus concurrent primitives in Scala. As an example, the definition of a two-place buffer using the pilib library looks like:

 def Buffer[a](put: Chan[a], get: Chan[a]) {
   def B0 { choice ( put * { x => B1(x) } ) }
   def B1(x: a) { choice ( get(x) * B0, put * { y => B2(x, y) } ) }
   def B2(x: a, y: a) { choice ( get(x) * B1(y) ) }


  1. AnyRef
  2. Any

Type Members

  1. class Chan[A] extends UChan with (A) ⇒ Product[A]

    Name on which one can emit, receive or that can be emitted or received during a communication

  2. class GP[a] extends AnyRef

    Typed guarded process

  3. class Product[A] extends AnyRef

  4. class Spawn extends AnyRef

    Run several processes in parallel using the following syntax: spawn < p1 |

  5. class Sum(gs: List[UGP]) extends Product

  6. class UChan extends AnyRef

    Untyped channel

  7. class UGP(n: UChan, polarity: Boolean, v: Any, c: (Any) ⇒ Any) extends Product

    An untyped guarded process

Value Members

  1. def choice[A](s: GP[A]*): A

    Pi-calculus non-deterministic choice

    Pi-calculus non-deterministic choice.





  2. def equals(arg0: Any): Boolean

    This method is used to compare the receiver object (this) with the argument object (arg0) for equivalence

    This method is used to compare the receiver object (this) with the argument object (arg0) for equivalence.

    The default implementations of this method is an equivalence relation:

    • It is reflexive: for any instance x of type Any, x.equals(x) should return true.
    • It is symmetric: for any instances x and y of type Any, x.equals(y) should return true if and only if y.equals(x) returns true.
    • It is transitive: for any instances x, y, and z of type AnyRef if x.equals(y) returns true and y.equals(z) returns true, then x.equals(z) should return true.

    If you override this method, you should verify that your implementation remains an equivalence relation. Additionally, when overriding this method it is often necessary to override hashCode to ensure that objects that are "equal" (o1.equals(o2) returns true) hash to the same Int (o1.hashCode.equals(o2.hashCode)).


    the object to compare against this object for equality.


    true if the receiver object is equivalent to the argument; false otherwise.

    definition classes: AnyRef ⇐ Any
  3. def hashCode(): Int

    Returns a hash code value for the object

    Returns a hash code value for the object.

    The default hashing algorithm is platform dependent.

    Note that it is allowed for two objects to have identical hash codes (o1.hashCode.equals(o2.hashCode)) yet not be equal (o1.equals(o2) returns false). A degenerate implementation could always return 0. However, it is required that if two objects are equal (o1.equals(o2) returns true) that they have identical hash codes (o1.hashCode.equals(o2.hashCode)). Therefore, when overriding this method, be sure to verify that the behavior is consistent with the equals method.

    definition classes: AnyRef ⇐ Any
  4. val spawn: Spawn

  5. def toString(): String

    Returns a string representation of the object

    Returns a string representation of the object.

    The default representation is platform dependent.

    definition classes: AnyRef ⇐ Any