Range

The names of the product elements

The name of the type

Check that list contains at least a certain number of elements.

Truncate a value so it stays within some range.

scala> clamp(5, 10, 15)
10

scala> clamp(5, 10, 0)
5

Construct a range which is unaffected by the size parameter.

A range from 0 to 10, with the origin at 0:

scala> Range.constant(0, 10).bounds(x)
(0,10)

scala> Range.constant(0, 10).origin
0

Construct a range which is unaffected by the size parameter with a origin point which may differ from the bounds.

A range from -10 to 10, with the origin at 0:

scala> Range.constantFrom(0, -10, 10).bounds(x)
(-10,10)

scala> Range.constantFrom(0, -10, 10).origin
0

A range from 1970 to 2100, with the origin at 2000:

scala> Range.constantFrom(2000, 1970, 2100).bounds(x)
(1970,2100)

scala> Range.constantFrom(2000, 1970, 2100).origin
2000

Construct a range which scales the second bound relative to the size parameter.

scala> Range.linear(0, 10).bounds(Size(1))
(0,0)

scala> Range.linear(0, 10).bounds(Size(50))
(0,5)

scala> Range.linear(0, 10).bounds(Size(100))
(0,10)

Construct a range which scales the second bound relative to the size parameter.

This works the same as 'linear', but for fractional values.

Construct a range which scales the bounds relative to the size parameter.

This works the same as linearFrom, but for fractional values.

Construct a range which scales the second bound relative to the size parameter.

scala> Range.linearFrom(0, -10, 10).bounds(Size(1))
(0,0)

scala> Range.linearFrom(0, -10, 20).bounds(Size(50))
(-5,10)

scala> Range.linearFrom(0, -10, 20).bounds(Size(100))
(-10,20)

Scale an integral linearly with the size parameter.

Scale a fractional number linearly with the size parameter.

Construct a range which represents a constant single value.

scala> Range.singleton(5).bounds(x)
(5,5)

scala> Range.singleton(5).origin
5